2x^2+45x-9900=0

Solution for 2x^2+45x-9900=0 equation:

2x^2+45x-9900=0

a = 2; b = 45; c = -9900;
Δ = b2-4ac
Δ = 452-4·2·(-9900)
Δ = 81225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81225}=285$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-285}{2*2}=\frac{-330}{4}
=-82+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+285}{2*2}=\frac{240}{4}
=60
$